x^2=8x+35

Solution for x^2=8x+35 equation:

x^2=8x+35

We move all terms to the left:

x^2-(8x+35)=0

We get rid of parentheses

x^2-8x-35=0

a = 1; b = -8; c = -35;
Δ = b2-4ac
Δ = -82-4·1·(-35)
Δ = 204
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{204}=\sqrt{4*51}=\sqrt{4}*\sqrt{51}=2\sqrt{51}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-8)-2\sqrt{51}}{2*1}=\frac{8-2\sqrt{51}}{2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-8)+2\sqrt{51}}{2*1}=\frac{8+2\sqrt{51}}{2}
$